InterviewSolution
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InterviewSolution
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Show thatthe equation `x^2+a x-4=0`has realand distinct roots for all real values of `a`. |
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Answer» The given equation is `x^(2)-ax-4=0.` This is of the form `Ax^(2)+Bx+C=0,` where A=1, B=a and C=-4. `:." "D=(B^(2)-4AC)={a^(2)-4xx1xx(-4)}=(a^(2)+16)bt0` fro all real values of a. Thus, `Dgt0` for all real values of a. Hence, the given equation has real and distinct roots for all real values of a. |
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