Saved Bookmarks
| 1. |
show the straight line x-2y+3=0 6x+3y+8=0 are perpendicular |
|
Answer» Given straight lines are x - 2y + 3 = 0 ⇒ 2y = x+3 ⇒ y = x/2 + 3/2 .......(1) And 6x+3y+8 = 0 ⇒ 3y = -6x - 8 ⇒ y = -2x - 8/3 ........(2) The slope of line (1) is m1 = 1/2 (By comparing equation y = mx + c) And slope of line (2) is m2 = -2 We obsened that m1 m2 = 1/2 x -2 = -1 which is condition that both lines are pependicular. Hence, given lines are pependicular to each other. |
|