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Showthat impulse is the changeof momentum |
Answer» <html><body><p></p>Solution : According to Newton.s <a href="https://interviewquestions.tuteehub.com/tag/second-1197322" style="font-weight:bold;" target="_blank" title="Click to know more about SECOND">SECOND</a> Law <br/>`F = (dp)/(dt)` i.e., dp = Fdt <br/> Integrate it over a <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> interval from `t_i` to `t_f` <br/> `int_(i)^(f) dp = int_(t_i)^(t_f) Fdt` <br/> `P_f - P_i = int_(t_1)^(t_2) F.dt` <br/>`P_i to` Intial momentum of the <a href="https://interviewquestions.tuteehub.com/tag/object-11416" style="font-weight:bold;" target="_blank" title="Click to know more about OBJECT">OBJECT</a> at ` t_i` <br/>`P_f to` Final momentum of the object at `t_f `<br/>`P_f - P_i = Delta p` = change in momentum during the time interval `Delta t. int_(t_i)^(t_f) Fdt = <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>` is called the impulse . <br/> If the force is constant over the time interval `Delta t` , then<br/> `int_(t_i)^(t_f) Fdt = F int_(t_i)^(t_f) dt = F (t_f - t_i)= F Delta t` <br/> `J= F Delta t = Delta p`</body></html> | |