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SI unit of Stefan-Boltzmaan constant is. . .. . . .

Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/wm-744315" style="font-weight:bold;" target="_blank" title="Click to know more about WM">WM</a>^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)K^(-4)`<br/>`Wm^(-2)`<br/>`Wm^(-2) K^(-<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>`Wm^(-2)K^(-2)`<br/></p>Solution :From stefan-Boltzman.s law <br/> `W-A e sigma T^(4)e=1` (<a href="https://interviewquestions.tuteehub.com/tag/emissivity-15409" style="font-weight:bold;" target="_blank" title="Click to know more about EMISSIVITY">EMISSIVITY</a>- unitless) <br/> `:.(W)/(AT^(4)t)= sigma` <br/> `:.` <a href="https://interviewquestions.tuteehub.com/tag/units-1438468" style="font-weight:bold;" target="_blank" title="Click to know more about UNITS">UNITS</a> of `sigma=(J)/(m^(2)K^(4)s)` <br/> `=(W)/(m^(2)K^(-4))`</body></html>


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