InterviewSolution
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सिद्ध कीजिए कि `Delta=|{:(a,a+b,a+b+c),(2a,3a+2b,4a+3b+2c),(3a,6a+3b,10+6b+3c):}|=a^(3).` |
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Answer» `Delta=|{:(a,a+b,a+b+c),(2a,3a+2b,4a+3b+2c),(3a,6a+3b,10+6b+3c):}|=a^(3).` `=|{:(a,a+b,a+b+c),(0,a,2a+b),(3a,6a+3b,10a+6b+3c):}|,R_(2)toR_(2)-2R_(1)`के प्रयोग से `|{:(a,a+b,a+b+c),(0,a,2a+b),( 0, 3a,7a+3b):}|,R_(3)to R_(3)-3R_(1)`के प्रयोग से `C_(1)` के अनुदिश प्रयास करने पर, `Delta=a[a(7a+3b)-3a(2a+b)]` `=a(7a^(2)+3ab-6a^(2)-3ab)]` `=a(a^(2))=a^(3).` |
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