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सिद्ध कीजिए कि `tan^(-1)((cosx)/(1+sinx))=(pi)/(4)-(x)/(2)` |
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Answer» बायाँ पक्ष `tan^(-1)((cosx)/(1+sinx))=tan^(-1)[(sin((pi)/(2)-x))/(1+cos((pi)/(2)-x))]` `=tan^(-1)[(2sin((pi)/(4)-(x)/(2))cos((pi)/(4)-(x)/(2)))/(2cos^(2)((pi)/(4)-(x)/(2)))]` `=tan^(-1)[(sin((pi)/(4)-(x)/(2)))/(cos((pi)/(4)-(x)/(2)))]` `=tan^(-1)[tan((pi)/(4)-(x)/(2))]=(pi)/(4)-(x)/(2)` `impliestan^(-1)((cosx)/(1+sinx))=(pi)/(4)-(x)/(2)="दायाँ पक्ष "` |
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