1.

सिद्ध कीजिए कि `tan^(-1)((cosx)/(1+sinx))=(pi)/(4)-(x)/(2)`

Answer» बायाँ पक्ष `tan^(-1)((cosx)/(1+sinx))=tan^(-1)[(sin((pi)/(2)-x))/(1+cos((pi)/(2)-x))]`
`=tan^(-1)[(2sin((pi)/(4)-(x)/(2))cos((pi)/(4)-(x)/(2)))/(2cos^(2)((pi)/(4)-(x)/(2)))]`
`=tan^(-1)[(sin((pi)/(4)-(x)/(2)))/(cos((pi)/(4)-(x)/(2)))]`
`=tan^(-1)[tan((pi)/(4)-(x)/(2))]=(pi)/(4)-(x)/(2)`
`impliestan^(-1)((cosx)/(1+sinx))=(pi)/(4)-(x)/(2)="दायाँ पक्ष "`


Discussion

No Comment Found