1.

सिद्ध कीजिए कि - `tan{(pi)/(4)+(1)/(2)cos^(-1).(a)/(b)}+tan{(pi)/(4)-(1)/(2)cos^(-1).(a)/(b)}=(2b)/(a).`

Answer» माना `cos^(-1)((a)/(b))=theta,` तब `cos theta=(a)/(b)`
`therefore L.H.S.=tan((pi)/(4)+(theta)/(2))+tan((pi)/(4)-(theta)/(2))`
`=(1+tan.(theta)/(2))/(1-tan.(theta)/(2))+(1-tan.(theta)/(2))/(1-tan.(theta)/(2))+=((1+tan.(theta)/(2))^(2)+(1-tan.(theta)/(2))^(2))/((1-tan^(2).(theta)/(2)))`
`=2((1+tan^(2).(theta)/(2))/(1-tan^(2).(theta)/(2)))=(2)/(cos theta)=(2b)/(a)`
= R.H.S.
यही सिद्ध करना था ।


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