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सिद्ध कीजिए - `"sin"^(-1)(3)/(5)-"sin"^(-1)(8)/(17)="cos"^(-1)(84)/(85)`. |
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Answer» L.H.S. `= "sin"^(-1)(3)/(5)-"sin"^(-1)(8)/(17)` `=cos^(-1)sqrt(1-((3)/(5))^(2))-cos^(-1)sqrt(1-((8)/(17))^(2))` `= cos^(-1)sqrt(1-(9)/(25))-cos^(-1)sqrt(1-(64)/(289))` `= "cos"^(-1)(4)/(5)-"cos"^(-1)(15)/(17)` `= cos^(-1)[(4)/(5)xx(15)/(17)+sqrt(1-((4)/(5))^(2))sqrt(1-((15)/(17))^(2))]` `= cos^(-1)[(60)/(85)+(3)/(5)xx(8)/(17)]` `= cos^(-1)((60)/(85)+(24)/(85))` `= cos^(-1)((84)/(85))` = R.H.S. यही सिद्ध करना था | |
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