1.

सिद्ध कीजिए- `tan^(-1)""((cos x-sinx)/(cos x+ sinx ))=(pi)/(4)-x`

Answer» यहाँ `(cos x-sinx )/(cosx+sinx)=(cosx(1-(sinx)/(cosx)))/(cosx(1+(sinx)/(cosx)))=(1-tanx)/(1+tanx)=(1-tanx)/(1+1*tanx)`
`=(tan""(pi)/(4)-tanx)/(1+tan""(pi)/(4)tanx)=tan""((pi)/(4)-x)`
`:.` बायाँ पक्ष `= tan^(-1)""((cosx-sinx)/(cosx+sinx))`
` =tan^(-1)[tan""((pi)/(4)-x)]=(pi)/(4)-x=` दायाँ पक्ष


Discussion

No Comment Found