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सिद्ध कीजिए- `tan^(-1)""((cos x-sinx)/(cos x+ sinx ))=(pi)/(4)-x` |
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Answer» यहाँ `(cos x-sinx )/(cosx+sinx)=(cosx(1-(sinx)/(cosx)))/(cosx(1+(sinx)/(cosx)))=(1-tanx)/(1+tanx)=(1-tanx)/(1+1*tanx)` `=(tan""(pi)/(4)-tanx)/(1+tan""(pi)/(4)tanx)=tan""((pi)/(4)-x)` `:.` बायाँ पक्ष `= tan^(-1)""((cosx-sinx)/(cosx+sinx))` ` =tan^(-1)[tan""((pi)/(4)-x)]=(pi)/(4)-x=` दायाँ पक्ष |
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