Side of a cube is measured with 2% error. Find error in its volume.

1.	Side of a cube is measured with 2% error. Find error in its volume.
Answer» Volume =a³So V=3×2 =6%<br>Given:Percentage error in measurement of side of cube = 2 %i.e., (Δa/a) × 100 = 2 %To Find:Percentage error in the volume and area of cube.Calculation:- Area of cube, A = a²⇒ Percent error in area is given by(ΔA/A) × 100 =2 (Δa/a) × 100⇒ (ΔA/A) × 100 = 2 × 2⇒ (ΔA/A) × 100 = 4 %- Volume of cube, V = a³⇒ Percent error in volume is given by(ΔV/V) × 100 = 3 (Δa/a) × 100⇒ (ΔV/V) × 100 = 3 × 2⇒ (ΔV/V) × 100 = 6 %- Thus, % error in area and volume is 4 % and 6 % respectively.<br>The error will be 4%

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