Sides of atriangle a, b, c. If s-a=4cm, s-b=8, s-c=12 then find the value of a, b, c.

Sides of atriangle a, b, c. If s-a=4cm, s-b=8, s-c=12 then find the va

1.	Sides of atriangle a, b, c. If s-a=4cm, s-b=8, s-c=12 then find the value of a, b, c.
Answer» Value of a = 20 , b = 16 and c =12. If a, b, c are sides of triangle thens=(a+b+c)/2Given:s-a=4 cms-b=8 cms-c=12 cmAdding these we gets+s+s-a-b-c = 243s-(a+b+c) =243s-2s = 24s = 24Now,s-a=424 - a =4a = 24 - 4 = 20 cms-b=824 - b = 8b = 24 - 8 = 16 cms - c = 1224 - c = 12c = 24 -12 = 12 cm