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सिध्द कीजिए कि- `1+(1)/(1+2)+(1)/(1+2+3)+(1)/(1+2+3+4)+…oo=2` |
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Answer» (iv)माना n वाँ पद `T_(n)`है, तब `T_(n)=(1)/(1+2+3+....+4)=(1)/(Sigman)=(1)/((n(n+1))/(2))=(2)/(n(n+1))=2((1)/(n)-(1)/(n+1))` अब `" "S_(n)=T_(1)+T_(2)+....T_(n)` `=2[{1-(1)/(2)}+{(1)/(2)-(1)/(3)}+{(1)/(3)-(1)/(4)}+...+{(1)/(n)-(1)/(n+1)}]` `=2(1-(1)/(n+1))=2)(n)/(n+1))` इसलिये,`" "S_(oo)=underset(n to oo)lim S_(n)=underset(n to oo)lim[2{1-(1)/(n+1)}]=2(1-(1)/(oo))=2=दायाँ पक्ष` |
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