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`Sigma_(n=1)^(13)(i^(n)+i^(n+1))`का मान ज्ञात कीजिए | |
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Answer» Correct Answer - i-1 `underset(n=1)overset(13)Sigma (i^(n)+i^(n+1))=i+i^(2)+i^(3)+…+i^(13)+i^(14)` `=i+2[i^(2)+i^(3)…i^(13)]-1=i+2[(i^(2)(1-i^(12)))/(1-i)]-1` `=i+2[(-1(1-(i^(2))^(6)))/(1-i)]-1=i-1` |
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