Silver chloride dissolves in excess of `NH_4OH`. The cation present in solution is.A. `Ag^(+)`B. `[Ag(NH_(3))_(4)]^(+)`C. `[Ag(NH_(3))_(2)]^(+)`D. `[Ag(NH_(3))_(6)]^(+)`

Silver chloride dissolves in excess of `NH_4OH`. The cation present in

1.	Silver chloride dissolves in excess of `NH_4OH`. The cation present in solution is.A. `Ag^(+)`B. `[Ag(NH_(3))_(4)]^(+)`C. `[Ag(NH_(3))_(2)]^(+)`D. `[Ag(NH_(3))_(6)]^(+)`
Answer» Correct Answer - C `AgCl+2NH_(4)OH underset("Diammine silver(I) chloride")(rarr[Ag(NH_(3))_(2)]Cl+2H_(2)O)`

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Silver chloride dissolves in excess of `NH_4OH`. The cation present in solution is.A. `Ag^(+)`B. `[Ag(NH_(3))_(4)]^(+)`C. `[Ag(NH_(3))_(2)]^(+)`D. `[Ag(NH_(3))_(6)]^(+)`

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