Silver chloride was prepared in two ways : (i) 0.5 g of a silver wire was dissolved in concentrated nitric acid and the excess of hydrochloric acid was added to it. The precipitate of silver chloride was separated by filtration, washed, dried and then weighed. The weight of the residue was found to be 0.66 g (ii) In another experiement, 1g of silver metal was heated in a current of chlorine till it was completely converted into its chloride which was found to weight 1.32 g Show that the data is according to the Law of Constant composition.

Silver chloride was prepared in two ways : (i) 0.5 g of a silver wire

1.	Silver chloride was prepared in two ways : (i) 0.5 g of a silver wire was dissolved in concentrated nitric acid and the excess of hydrochloric acid was added to it. The precipitate of silver chloride was separated by filtration, washed, dried and then weighed. The weight of the residue was found to be 0.66 g (ii) In another experiement, 1g of silver metal was heated in a current of chlorine till it was completely converted into its chloride which was found to weight 1.32 g Show that the data is according to the Law of Constant composition.
Answer» Solution :In the first experiment Mass of SILVER = 0.5 G , Mass of silver chloride = 0.66 g PERCENTAGE of silver `= ((0.50g))/((0.66g))xx100=75.76%` Percentage of CHLORINE `= 100 -75.76 = 24.24 %` In the second experiment Mass of silver = 1.0 g , Mass of silver chloride = 1.32 g Percentage of silver `= ((1.0g))/((1.32g))xx100=75.76%` percentage of chlorine `= 100 - 75.76 = 24.24 %` The results are in accordance with the LAW of Constant Composition.