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Silver crystallises in a face-centred cubic unit cell. The density of Ag is `10.5 g cm^(-3)` . Calculate the edge length of the unit cell. |
Answer» For face-centred cubic unit, Z=4 We know that , `V=(ZxxM)/(N_(0)xxd)` `=(4xx108)/((6.023xx10^(23))xx10.5)=6.83xx10^(-23)` `=68.3xx10^(-24)` Let a be the edge length of the unit cell. So, `V=a^(3)` or `a^(3)=68.3xx10^(-24)` `a=(68.3xx10^(-24))^(1//3) cm` `=4.09xx10^(-8)` cm =409 pm |
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