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| 1. |
Silver crystallises in fcc lattice. If the edge length of the cell in4.077 xx 10^(-8) cm and densityis 0.5 g cm^(-3) , calculate the atomic mass of silver. |
| Answer» SOLUTION : ` M =( p xx a^(3) xx N_(0))/ Z = ( 10.5 " g cm"^(-3) xx ( 4.077 xx 10^(-8) cm)^(3) xx(6.02 xx 10^(23) "MOL"^(-1)))/4 = 107.09 " g mol"^(-1)` | |