1.

Silver crystallises in fcc lattice. If the edge length of the cell is 4.077xx10^(-8) cmand density is 10.5 "g cm"^(-3), calculate the atomic mass of silver.

Answer»

Solution :`M=(rhoxxa^3xxN_0)/Z=(10.5 "G CM"^(-3) XX (4.077xx10^(-8) cm)^3 xx(6.02xx10^23 "mol"^(-1)))/4=107.09 "g mol"^(-1)`


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