Silver forms ccp lattice and X-ray studies of its crystals show that the edge length of its unit cell is 408.6pm. Calculate the density of silver (Atomic mass =107.9 u)

Silver forms ccp lattice and X-ray studies of its crystals show that t

1.	Silver forms ccp lattice and X-ray studies of its crystals show that the edge length of its unit cell is 408.6pm. Calculate the density of silver (Atomic mass =107.9 u)
Answer» Solution :`rho=(ZxxM)/(a^3xxN_0)` For CCP lattice (which is EQUIVALENT to fcc lattice ), Z=4 ATOMS/unit cell Also we are GIVEN that `M=107.9 g mol^(-1)` a=408.6 pm=`408.6xx10^(-12)` cm `therefore rho=(4 "atoms"xx107.9g mol^(-1)) /((408.6xx10^(-12)cm)^3 (6.022xx10^23 "atoms mol"^(-1))=10.5 g cm^(-3)`