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Silver has work function of 4.7 eV when ultraviolet light of wavelength 100 nm is incident upon it, a potential of 7.7 volt is required to stop the photoelectrons from reaching the collector plate. What will be the minimum de-Broglie wavelength of photoelectrons when the wavelength of incident radiations is increased by 100% ? |
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Answer» 3.3 Å When the wavelength is increased by 100% then energy of incident photon wil be `6.2 eV` then `K_("max") = E - 4.7 = 6.2 - 4.7 = 1.5 eV` `:. lambda_(dB) = SQRT((150)/(V)) = sqrt((150)/(1.5))` Å = 10 Å. |
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