1.

Silver metal crystallises with a face-centred cubic lattice. The length of the unit cell is found to be 3.0 xx 10^(-8) cm. Calculate the atomic radius and density of silver. (Molar mass of Ag = 108 g mol^(-1), N_A =6.02xx 10^23mol^(-1))

Answer»


SOLUTION :`a=3.0xx10^(-8)` cm. For fcc, `r=a/(2sqrt2)=(3.0xx10^(-8))/(2xx1.414)=1.06xx10^(-8)` cm
`rho=(ZxxM)/(a^3xxN_A)=(4xx108)/((3.0xx10^(-8))^3xx(6.02xx10^23))=26.6 "G cm"^(-3)`


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