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Simple interest on a certain sum is given by `l=(PTR)/(100)`. Make T as the subject of the formula. Find T when P=rs1000, R=10% p.a., and l=rs 300.A. `T=(100l)/(PR),6` yearsB. `T=(100l)/(PR),3` yearsC. `T=(100P)/(IR),4` yearsD. `T=(100R)/(Pl):5` years. |
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Answer» Correct Answer - B `I=(PTR)/(100)` `rArr 100 I=PTRrArr(100I)/(PR)=TrArrT=(100I)/(PR)` Given `P=rs1000,R=10%` p.a, and `I=300` `therefore T=(100xx300)/(1000xx10)=3` years. |
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