1.

Simple pendulum is executing simple harmonic motion with time period `T`. If the length of the pendulum is increased by `21%`, then the increase in the time period of the pendulum of the increased length is:A. 0.22B. 0.2C. 0.33D. 0.44

Answer» Correct Answer - B
`(T_(2))/(T_(1))=sqrt((l_(2))/(l_(1)))=sqrt(1.44)=1.2`
`(T_(2)-T_(1))/(T_(1))=1.2-1=0.2=20%`.


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