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Simplest alkene (A) reacts with HCl to form compound (B). Compound (B) reacts with ammonia to form compound (C) of molecular formula C_(2)H_(7)N. Compound (C) undergoes carbylamine test. Identify (A), (B), and (C). |
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Answer» Solution :`UNDERSET("(A) Ethene")(CH_(2)=CH_(2))+HCl to underset("(B) Chloroethane")(CH_(3)-CH_(2)Cl)` `underset("(B) Chloroethane")(CH_(3)CH_(2)Cl)+NH_(3) to underset("(C) amine")(CH_(3)CH_(2)NH_(2))` A `CH_(2)=CH_(2)`Ethene B `CH_(3)CH_(2)Cl`Chloroethane C `CH_(3)CH_(2)NH_(2)`ETHYLAMINE. |
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