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Simplification of the Boolean expression (A + B)’(C + D + E)’ + (A + B)’ yields which of the following results?(a) A + B)(b) A’B’(c) C + D + E(d) C’D’E’(e) A’B’C’D’E |
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Answer» (A + B)'(C + D + E)' + (A + B)'=(A+B)’((C+D+E)+1) (Distb. Law) =(A+B)’.1 (Identity Law) =(A+B)’ (Identity Law) =A’B’ (DeMorgan’s Law) So, simplification of the Boolean expression (A + B)’(C + D + E)’ + (A + B)’ yields |
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