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Simplify(3^(n-2)*9^(2-n))/(3^(2-n)) |
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Answer» Solution :In order to combine exponents USING the PROPERTIES above, the BASE of each factor must be the same `(3^(n-2)*9^(2-n))/(3^(2-n))=(3^(n-2)*(3^(2))^(2-n))/(3^(2-n))=(3^(n-2)*3^(4-2n))/(3^(2-n))` `=3^(n-2+4-2n-(2-n))=3^(0)=1` |
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