1.

Simplify(3^(n-2)*9^(2-n))/(3^(2-n))

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Solution :In order to combine exponents USING the PROPERTIES above, the BASE of each factor must be the same
`(3^(n-2)*9^(2-n))/(3^(2-n))=(3^(n-2)*(3^(2))^(2-n))/(3^(2-n))=(3^(n-2)*3^(4-2n))/(3^(2-n))`
`=3^(n-2+4-2n-(2-n))=3^(0)=1`


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