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Simplify: (a + b + c) + (2a + 3b – c) – (4a + b – 2c) |
Answer» Given (a + b + c) + (2a + 3b – c) – (4a + b – 2c) = a + b + c + 2a + 3b – c – 4a – b + 2c = (a + 2a – 4a) + (b + 3b – b) + (c – c + 2c) = (1 + 2 – 4)a + (1 + 3 – 1)b + (1 – 1 + 2)c = (- 1) a + 3b + 2c = – a + 3b + 2c |
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