1.

Simplify:(a + b) (c – d) + (a – b) (c + d) + 2 (ac + bd)

Answer»

(a + b) (c – d) + (a – b) (c + d) + 2(ac + bd)

(a + b) (c – d) + (a -b) (c + d) + 2(ac + bd)

= a (c – d) + b(c – d) + a(c + d) – b(c + d) + 2 (ac + bd)

= ac – ad + bc – bd + ac + ad – bc – bd + 2 ac + 2 bd

= ac + ac + 2ac – ad + ad + be – bc – bd – bd – 2 bd

= 4ac



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