InterviewSolution
Saved Bookmarks
| 1. |
Simplify by rationalising the denominator 10/5 sq root -3 sq root 5 with method |
| Answer» For rationalising the denominator of any number 1/√a-b , we multiply it by √a+b/√a+b.=10/√5-3× √5+3/√5+3=10×√5+3/5+(3)²=10√5+3/14 | |