Simplify: (i) (16−15)52 (ii) 5√(32)−3 (iii) 3√(343)−2 (iv) (

1.	Simplify: (i) (16−15)52 (ii) 5√(32)−3 (iii) 3√(343)−2 (iv) (0.001)13 (v) (25)32×(243)35(16)54×(8)43 (vi) (√25)8÷(√25)13 (vii) (5−1×7252×7−4)72×(5−2×7353×7−5)−52
Answer» Simplify: (i) $(16^{\frac{- 1}{5}})^{\frac{5}{2}}$ (ii) $\sqrt[5]{(32)^{- 3}}$ (iii) $\sqrt[3]{(343)^{- 2}}$ (iv) $(0.001)^{\frac{1}{3}}$ (v) $\frac{(25)^{\frac{3}{2}} \times (243)^{\frac{3}{5}}}{(16)^{\frac{5}{4}} \times (8)^{\frac{4}{3}}}$ (vi) ${(\frac{\sqrt{2}}{5})}^{8} \div {(\frac{\sqrt{2}}{5})}^{13}$ (vii) ${(\frac{5^{- 1} \times 7^{2}}{5^{2} \times 7^{- 4}})}^{\frac{7}{2}} \times {(\frac{5^{- 2} \times 7^{3}}{5^{3} \times 7^{- 5}})}^{\frac{- 5}{2}}$

Simplify: (i) (16−15)52 (ii) 5√(32)−3 (iii) 3√(343)−2 (iv) (0.001)13 (v) (25)32×(243)35(16)54×(8)43 (vi) (√25)8÷(√25)13 (vii) (5−1×7252×7−4)72×(5−2×7353×7−5)−52

Answer»

Simplify:

(i) $(16^{\frac{- 1}{5}})^{\frac{5}{2}}$

(ii) $\sqrt[5]{(32)^{- 3}}$

(iii) $\sqrt[3]{(343)^{- 2}}$

(iv) $(0.001)^{\frac{1}{3}}$

(v) $\frac{(25)^{\frac{3}{2}} \times (243)^{\frac{3}{5}}}{(16)^{\frac{5}{4}} \times (8)^{\frac{4}{3}}}$

(vi) ${(\frac{\sqrt{2}}{5})}^{8} \div {(\frac{\sqrt{2}}{5})}^{13}$

(vii) ${(\frac{5^{- 1} \times 7^{2}}{5^{2} \times 7^{- 4}})}^{\frac{7}{2}} \times {(\frac{5^{- 2} \times 7^{3}}{5^{3} \times 7^{- 5}})}^{\frac{- 5}{2}}$

Discussion

No Comment Found

Related InterviewSolutions

Given, tan(A+B)=√3 and tan(A−B)=1√3If B<A<90∘, then, find the values of A and B in degrees.
Represent -25.6875 in rational form.
Factorise:25x2 – 10x + 1 – 36y2
1.How many pairs of adjacent angles are formed when two lines intersect in a point?
if x=squareroot3 + 1 /2 then value of 4x^3 +2x^2-8x+7 is??
Question 1In the figure, PSDA is a parallelogram. Points Q and R are taken on PS such that PQ = RS and PA || QB || RC. Prove that ar (PQE) = ar (CFD).
Question 1(ii) Do the following pair of linear equations have no solution? Justify your answer. x = 2y and y = 2x
In a parallelogram ABCD, ∠D = 135°, determine the measures of ∠A and ∠B.
The value of (2x−3y)3+(x+3y)3+3(2x−3y)2(x+3y)+3(2x−3y)(x+3y)2=
Number of real zero(s) of polynomial f(y) = ay2 + by + c, is

Simplify: (i) (16−15)52 (ii) 5√(32)−3 (iii) 3√(343)−2 (iv) (0.001)13 (v) (25)32×(243)35(16)54×(8)43 (vi) (√25)8÷(√25)13 (vii) (5−1×7252×7−4)72×(5−2×7353×7−5)−52

Discussion

No Comment Found

Related InterviewSolutions

Reply to Comment