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Simplify : (i) `2^(2/3). 2^(1/5)` (ii) `(1/(3^3))^7` (iii) `(11^(1/2))/(11^(1/4))` (iv) `7^(1/2). 8^(1/2)` |
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Answer» (i) `2^(2/3).2^(1/5)` As, `a^m.a^n = a^(m+n)` `2^(2/3).2^(1/5)= 2^(2/3+1/5)=2^(13/15)` (ii) `(1/3^3)^7` As, `(a^m)^n)= a^(mn)` `(1/3^3)^7 = 1/3^21 = 3^-21` (iii) `(11^1/2)/(11^1/4)` As, `a^m/a^n = a^(m-n)` `(11^1/2)/(11^1/4)=11^(1/2-1/4) = 11^(1/4)` (iv)`7^(1/2).8^(1/2)` As, `a^m.b^m = (ab)^m` `7^(1/2).8^(1/2) = (7.8)^1/2 = 56^(1/2)` |
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