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| 1. |
Simplify : sq.root under 3 + 2sq.root2 |
| Answer» √(3 + 2√(2))=√(2 + 1 + 2√(2))(because 3 can be written as 2 + 1)=√(√(2)2 + 12 +2 √(2) 1)(because 2 can be written as √(2) 2 and 1 can be written as 1^2)It shows the identity: (a+b) 2 = a2 + b2 + 2abSo , it will become[√(2+1)] 2=(√2+1) 1/2*2=(√2+1) 1=√2+1 | |