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Simplify the Boolean expression (A + B + C)(D + E)’ + (A + B + C)(D + E) and choose the best answer.(a) A + B + C(b) D + E(c) A’B’C’(d) D’E’(e) None of these |
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Answer» (A+B+C)(D+E)' + (A+B+C)(D+E) = (A+B+C)((D+E)+(D+E)’) (Distributive Law) = (A+B+C).(1) (X+X’=1) = A+B+C So, simplification of the Boolean expression (A + B + C)(D + E)’ + (A + B + C)(D + E) yields A+B+C |
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