InterviewSolution
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InterviewSolution
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Simply: (16-1/5)5/2 |
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Answer» We have,{tex}\\left(16^{-\\frac{1}{5}}\\right)^{\\frac{5}{2}}{/tex}\xa0=\xa0{tex}16^{-\\frac{1}{5} \\times \\frac{5}{2}}{/tex}\xa0[as (am\u200b\u200b\u200b\u200b\u200b\u200b)n= am×n\xa0\u200b\u200b\u200b\u200b\u200b\u200b]\xa0=\xa0{tex}16^{-\\frac{1}{2}}{/tex}=\xa0{tex}\\frac{1}{16^{\\frac{1}{2}}}{/tex}=\xa0{tex}\\frac{1}{\\left(4^{2}\\right)^{\\frac{1}{2}}}{/tex}=\xa0{tex}\\frac{1}{4}{/tex}.\xa0 (16-1/5)5/2(80/5-1/5)5/279/5×5/2=79/2 |
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