1.

simply 3^n+3 + 3 ^n / 3^n+3 - 3^n+1

Answer»

\(\frac{3^{n+3}+3^n}{3^{n+3}-3^{n+1}}\) \(=\frac{3^n(3^3+1)}{3^{n+1}{(3^2-1)}}\)

\(=\frac{1}{3}\times\frac{27+1}{9-1}\) 

\(=\frac{28}{3\times8}\)

\(=\frac{7}{6}\)



Discussion

No Comment Found

Related InterviewSolutions