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\sin ^{2} 75^{\circ}-\sin ^{2} 15^{\circ}=\frac{\sqrt{3}}{2} |
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Answer» Sin²A - sin²B= Sin (A+B).Sin(A-B) Now sin²75 - sin²15 = sin 90 . sin 60 = 1.√3/2= √3/2Ans |
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