(sin(27^circ)^2 %2B sin(63^circ)^2)/(cos(17^circ)^2 %2B cos(73^circ)^2

1.	(sin(27^circ)^2 %2B sin(63^circ)^2)/(cos(17^circ)^2 %2B cos(73^circ)^2)
Answer» (i) sin^2 (63)+ sin^2(27)/ cos^2(17)+ sin^2(73)= cos^2(90-63)+ Sin^2(27)/ cos^2( 17)+ sin^2(90-73)= cos^2(17)+ sin^2(27)/ cos^2(17)+sin^2(27/=1. (ii) 1. 12.9921488722. 1 (ii)sin25 cos65+ cos25 sin 75=sin25 cos(90-65)+ cos(90'-17)+ cos^2(73)= sin25cos25+ sin^2(73) cos^2(73)=1 1)1 2 )1 is the correct answer of the given question.

(sin(27^circ)^2 %2B sin(63^circ)^2)/(cos(17^circ)^2 %2B cos(73^circ)^2)

Answer»

(i) sin^2 (63)+ sin^2(27)/ cos^2(17)+ sin^2(73)= cos^2(90-63)+ Sin^2(27)/ cos^2( 17)+ sin^2(90-73)= cos^2(17)+ sin^2(27)/ cos^2(17)+sin^2(27/=1. (ii)

1. 12.9921488722. 1

(ii)sin25 cos65+ cos25 sin 75=sin25 cos(90-65)+ cos(90'-17)+ cos^2(73)= sin25cos25+ sin^2(73) cos^2(73)=1

1)1 2 )1 is the correct answer of the given question.