InterviewSolution
Saved Bookmarks
| 1. |
`sin [ cos^(-1) (-(1)/(2))]` का मान निकालें| |
|
Answer» `= sin""(pi)/(3)-(-(pi)/(3))] = sin[(pi)/(3) + (pi)/(6)] = sin""(pi)/(2) =1` `= sin[pi - cos^(-1)""(1)/(2)] " "[because cos^(-1)(-(1)/(2)) = pi-cos^(-1)""(1)/(2)]` `= sin [pi-(pi)/(3) ] = sin ""(2pi)/(3) = (sqrt(3))/(2) " "[because cos^(-1)((1)/(2)) = (pi)/(3)]` |
|