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`sin [(pi)/(3)-sin^(-1)(-(1)/(2))]` का मान निकालें| |
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Answer» `sin[(pi)/(3) -sin^(-1)(-(1)/(2))]` ` = sin[(pi)/(3)-{-sin^(-1)((1)/(2))}] [because sin^(-1)(-x) = - sin^(-1)x, ]` `= sin""(pi)/(3)-(-(pi)/(3))] = sin[(pi)/(3) + (pi)/(6)] = sin""(pi)/(2) =1` |
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