1.

`sin [(pi)/(3)-sin^(-1)(-(1)/(2))]` का मान निकालें|

Answer» `sin[(pi)/(3) -sin^(-1)(-(1)/(2))]`
` = sin[(pi)/(3)-{-sin^(-1)((1)/(2))}] [because sin^(-1)(-x) = - sin^(-1)x, ]`
`= sin""(pi)/(3)-(-(pi)/(3))] = sin[(pi)/(3) + (pi)/(6)] = sin""(pi)/(2) =1`


Discussion

No Comment Found