1.

Sin²Ф+sin²Ф=1cos²Ф+cos⁴Ф=?

Answer»

Hey !!!

sin²¢ + sin²¢ = 1

2sin²¢ = 1

sin²¢ = 1/2

sin¢ = √1/2

sin¢ = sin45° ..

¢ = 45°

cos²¢ + cos⁴¢ = ??

cos²45° + cos⁴45°

= (1/√2)² + (1/√2)⁴

= 1/2 + 1/4

= 1/2+ 1 /4 = 2 + 1/4

= 3/4

= 0.75 Answer

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HOPE it helps you !!!

@Rajukumar111





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