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# sindin sinB =4, * sin(A + B) = ?

Answer»

sin(A+B)=sinAcosB+cosAsinBhencecosA=√1-sin^2A=√1-16/25=3/5and cosB=√1-sin^2B=√1-25/169=12/13hencesin(A+B)=4/5*3/5+12/13*5/13=12/25+60/169



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