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sine coseIn a AABC, AB AC and D is a point on side AC, such that BC2 - AC x CD. Prove that BD - BCicting of 3 red halls and 4 bla |
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Answer» Given: A △ABC in which AB = AC. D is a point on AC such that BC^2= AC × CD.To prove : BD = BCProof : Since BC^2= AC × CDTherefore BC × BC = AC × CDAC/BC = BC/CD .......(i)Also ∠ACB = ∠BCDSince △ABC ~ △BDC [By SAS Axiom of similar triangles]AB/AC = BD/BC ........(ii)But AB = AC (Given) .........(iii)From (i),(ii) and (iii) we getBD = BC. |
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