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| 1. |
sing properties of determinants, in Exercises 6 to 14, show that:10 a 6-a? ab ac-a 0 -cl=07.ba – bc =416 colca |
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Answer» |0 a -b||-a o -c||b c 0|= 0(0×0 - c×-c) + (-a )(-a×0 - b×-c) + (-b)(b×0 - -ac)= 0+ (-a)(bc) + (-b)(-ac)= -abc + abc=. 0 |
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