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sinSx + sin 3x 3 =tandxcos5x + cos3x |
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Answer» LHS : apply SIN A+ SIN B and COS A + COS B formulae 2sin4xcosx / 2cos4xcosx ( 2 and cos x get cancelled ) we are left with : sin4x / cos 4x = tan4x ( since , sinx / cosx = tanx ) |
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