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sinθ.tanθ = (A) \(\frac{sin^2\theta}{cos\theta}\)(B) \(\frac{sin\theta}{cos\theta}\)(C) \(\frac{cos^2\theta}{sin\theta}\)(D) cosθ |
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Answer» Correct option is: (A) \(\frac{sin^2\theta}{cos\theta}\) |
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