1.

Six boys A, B, C, D, E and F play a game of cards. Each has a pack of 10 cards. F borrows 2 cards from A and gives away 5 to C who in turn gives 3 to B while B gives 6 to D who passes 1 to E. Then the number of cards possessed by D and E is equal to the number of cards possessed by (a) A, B and C (b) B, C and F (c) A, B and F (d) A, C and F

Answer»

Correct option (b) B, C and F     

Explanation:

At the start all the boys have equal number of cards, as shown below:

A10
B10
C10
D10
E10
F10

Now, F borrows 2 cards from A and gives away 5 to C who in turn gives 3 to B:

A8
B13
C12
D10
E10
F 7

B gives 6 to D who passes on 1 to E. 

A8
B7
C12
D15
E11
F7

 Number of cards with D and E = 15 + 11 = 26

We can see that number of cards with B, C and F = 7 + 12 + 7 = 26 



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