1.

Six coin are tossed simultanously. Find the probability of getting no head.

Answer»

Let P be the probability of getting a head in the toss of a coin.

Then P = 1/2

Let q = prob of not getting a head = 1 - P = 1/2

Let X = number of success in the experiment 

So, X can take value 0,1,2,3,4,5,6 i.e., n = 6

Now P(x = r) = ncrpr.qn - r

So, P(no head) = P(x = 0) = 6c0(1/2)0.(1/2)(6 - 0) = 1/64



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