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Six coin are tossed simultanously. Find the probability of getting no head. |
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Answer» Let P be the probability of getting a head in the toss of a coin. Then P = 1/2 Let q = prob of not getting a head = 1 - P = 1/2 Let X = number of success in the experiment So, X can take value 0,1,2,3,4,5,6 i.e., n = 6 Now P(x = r) = ncrpr.qn - r So, P(no head) = P(x = 0) = 6c0(1/2)0.(1/2)(6 - 0) = 1/64 |
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