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Six fair dice are thrown independently. The probability that three are exactly `2` different pairs (A pair is an ordered combination like `2,2,1,3,5,6`) isA. `5//72`B. `26//72`C. `125//144`D. `5//36` |
Answer» Correct Answer - B `(b)` Total no of outcomes `=6^(6)` Number of ways of choosing `4` other different numbers is `"^(6)C_(2)` and choosing `2` out of remaining `4` can be lone in `"^(4)C_(2)` ways. Also numbr of ways of arranging `6` numbers of which `2` are alike and `2` are alike is `(6!)/(2!2!)` `:.` Required probability `=("^(6)C_(2)xx^(4)C_(2)xx(6)/(2!2!))/(6^(6))=(26)/(72)` |
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