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Six identical capacitors are joined in parallel, charged to a potential difference of 10 V, separated and then connected in series. Then the potential difference between the free plates isA. 10 VB. 30 VC. 60 VD. `(10/6)V` |
Answer» Correct Answer - C In parallel potential of each condenser is same `therefore" "V_(1)=V_(2)=V_(3)=V_(4)=V_(5)=V_(6)=10V` Now these condensers are connected is series. `therefore" "V=V_(1)=V_(2)=V_(3)=V_(4)=V_(5)=V_(6)` = 10 + 10 + 10 + 10 + 10 + 10 = 60 V |
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