1.

Six valence electrons of oxygen are labelled as AB in 2s orbitals and CD , E, f in rp_x, 2p_z and 2p0_y orbitals repectively . If spin quantum number of A, Cm F is 1/2 the group of electron with three of the quantum numbers same are :

Answer»

`[AB], [DEF]`
`[AB],[CEF],[AE]`
`[AD], [BDF]`
`[AB],[CE],[AE]`

SOLUTION :O has configuration `1 s , 2s^2 _x^2 2p-y^2 2p-z^1,`
`(AB)(C D) E F`
It is th famous Schro dinger waver eqation .


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